Roland iModela iM-01-3D Hobby Mill via Fabaloo…
Roland DG Corporation, a leading worldwide provider of 3D milling and engraving technologies, today introduced the new iModela iM-01. Incorporating 25 years of Roland’s proven 3D milling technology, the iModela is an inexpensive, easy-to-use desktop device that mills wax, foam, balsa wood and plastic materials commonly used in craft and hobby projects.
Make a robot friend with Adafruit’s CRICKIT – A Creative Robotics & Interactive Construction Kit. It’s an add-on to our popular Circuit Playground Express, FEATHER and other platforms to make and program robots with CircuitPython, MakeCode, and Arduino. Start controlling motors, servos, solenoids. You also get signal pins, capacitive touch sensors, a NeoPixel driver and amplified speaker output. It complements & extends your boards so you can still use all the goodies on the microcontroller, now you have a robotics playground as well.
Join 7,500+ makers on Adafruit’s Discord channels and be part of the community! http://adafru.it/discord
CircuitPython in 2018 – Python on Microcontrollers is here!
Have an amazing project to share? Join the SHOW-AND-TELL every Wednesday night at 7:30pm ET on Google+ Hangouts.
Join us every Wednesday night at 8pm ET for Ask an Engineer!
Follow Adafruit on Instagram for top secret new products, behinds the scenes and more https://www.instagram.com/adafruit/
Maker Business — Despite multiple bankruptcies, RadioShack continues to find ways to keep the lights on
Wearables — Molding with glue
Electronics — A few words on inductor resistance
Biohacking — Running Blades
Python for Microcontrollers — Help bring CircuitPython to other languages!
Sorry, the comment form is closed at this time.
Pricing?
I don’t see a milled PCB either 🙁
Cmon!
This site http://www.ubergizmo.com/2011/10/roland-imodela-im-01-3d-printer/
pegs it at $1000. I guess that’s not too bad for a mill. I wonder how hackable it will be – I suspect a PCB wouldn’t be too hard, given some time and effort.
Is it a mill, or 3d printer?